The map function creates [6, 21, 20]. After filtering for values divisible by 3, we get [6, 21]. The reduce then adds these filtered values to an initial accumulator of 5: 5 + 6 + 21 = 32. Therefore, the final output is 32.

The map function results in [6, 21, 20]. Only [6, 21] pass the filter, as they’re divisible by 3. The reduce adds 5 + 6 + 21 = 32. So, the final output is 32

The map produces [6, 21, 20], and the filter keeps [6, 21]. The reduce sums them, but it mistakenly adds the initial value 5 incorrectly, resulting in 30

The map function produces [6, 21, 20]. However, after filtering, only 6 and 21 are kept. The reduce then incorrectly sums 6 + 21 without including the initial value 5, resulting in 27